第17 題 (A) Her Christmas plan. (B) Tips on cooking Chinese dishes. (C) Her Chinese New Year experience.

第18 題 (A)(B)(C)

第19 題 (A) Don’t stop the train leaving. (B) Move to the center of the train. (C) Let other people get on the train.

第20 題 (A) He enjoyed it. (B) He did not like it. (C) He was sorry he didn’t eat it.

1.What is the IUPAC name of the following compound? (A) 1,4-dimethylbicyclo[3.3.0]octane (B)2,5-dimethylbicyclo[3.3.0]octane (C) 2,7-dimethylbicyclo[3.3.0]octane (D)1,6-dimethylbicyclo[3.3.0]octane (E) 3,8-dimethylbicyclo[3.3.0]Joctane

2.Which of the following choices represents the wedge/dash drawing of the Fischer projection shown on the left? (A)I (B) II (C) II] (D) IV (E) V

3.Which of the following describes the difference between protic and aprotic solvents? (A) protic soivents stabilize anions only. (B) aprotic solvents stabilize anions only. (C) protic soivents stabilize cations only. (D) aprotic solvents stabilize both cations and anions. (E) protic solvents stabilize both cations and anions.

4.Describe the major product(s) of the reaction below. (A) only one stereoisomer. (B) an equal mixture of enantiomers. (C) a mixture of diastereomers and their enantiomers. (D) a mixture of constitutional isomers. (E) a mixture of constitutional isomers and their enantiomers.

5. What functional group would be expected to be present in the final product of the reaction between 1-hexyne and a mixture of mercuric sulfate and aqueous sulfuric acid?? (A) aldehyde (B) ketone (C) diol (D) alkene (E) carboxylic acid

6.Explain whether the major product(s) of the following reaction is optically active and why this is the case. (A) The product is optically acive because a chiral center is created at the right side vertex of the ring. (B) The product is optically active because it has a chiral center at a terminal carbon. (C) The product is not optically active because it has a chiral center that is part of the ring. (D) The product is not optically active because its chiral center is not part of the ring. (E) The product is not optically active because it has no chiral centers.