11. Assuming that the combustion of hydrogen gas provides three times as much energy per gram as gasoline, calculate the volume of liquid H2 (density = 0.0710 g/mL) required to furnish the energy contained in 80.0 L (about 20 gal) of gasoline (density = 0.740 g/mL). Calculate also the volume that this hydrogen would occupy as a gas at 1.00 atm and 25°C. At 1.00 atm and 25°C, the hydrogen gas needed to replace 20 gal of gasoline occupies a volume of L.
(A) 277
(B) 19700
(C) 59200
(D) 239000
(E) 977000
詳解 (共 1 筆)
未解鎖
[(740x80/3)/2]x24.4=...