24. Consider the reaction: NH₃(g) + HCl(g) → NH₄Cl(s)
Given the following table of thermodynamic data at 298 K, the value of equilibrium constant for the reaction at 25 °C is ________. Substance ∆Hf o (kJ/mol)) So (J/K・mol) NH3(g) -46.19 192.5 HCl(g) -92.30 186.69 NH4Cl(s) -314.4 94.6
(A)150
(B)9.3×1015
(C)8.4×10⁴
(D)1.1×10-16
(E)7.2×1012

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統計： A(0), B(8), C(0), D(4), E(0) #2343745

cute_shiba

B1 · 2025/04/10

#6366845

Hrxn ＝ H⁰f product － H⁰f reactant

－314.4－(－46.19－92.3) ＝－175.91 KJ

Srxn ＝ S⁰f product － S⁰f reactant

94.6－(192.5＋186.69) ＝－284.59 J/K ＝－0.28459 KJ/K

G⁰ － H⁰ － TS⁰

＝－175.91－298*(－0.28459) ＝－91.1K J/mole ＝－91100 J/mole

G⁰＝－RTlnK

－91100 ＝－8.314*298*2.303logK

logK ＝ 15.96

K ＝ 10^15.96 ＝ 9.3*10^15