4.欲使用落球法測量某液體黏度,已知球體直徑為2mm,球體密度為5g/cm3,某液體密度為1.58g/cm3,球體在液體中落下200cm需20秒,求某液體黏度為多少P?
(A)0.372
(B)0.745
(C)2.979
(D)7.450
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統計: A(4), B(17), C(3), D(4), E(0) #3206478
統計: A(4), B(17), C(3), D(4), E(0) #3206478
詳解 (共 3 筆)
#6029766
Ut = h/t = (ρp - ρ) g Dp2 /18μ
= 2/20 = (5000-1580) x 9.8 (2x10-3) 2 / 18μ
μ = 0.07448 kg/ms
1 P = 0.1 kg/ms
0.07448 kg/ms x 1P /0.1( kg/ms) = 0.7448 P
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200cm=2m
1.58g/cm3 = 1580 kg/m3
5g/cm3 = 5000 kg/m3
2 mm = 2/1000 m =2x10-3
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