62. There is a titration of 50.00 mL of 0.0500 M Fe2+ with 0.1000 M Ce4+ in a medium (1.0 M H2SO4). Calculate the potential after the addition of 25.00 mL of Ce4+.
Ce4+ + e- → Ce3+ Eo = 1.44 V (1 M H2SO4)
Fe3+ + e- → Fe2+ Eo = 0.68 V (1 M H2SO4)
(A) 0.64 V
(B) 1.06 V
(C) 1.56 V
(D) 2.01 V
(E) 2.21 V