70. To form a buffer solution with pH = 9.0, how many moles of NH4Cl should be added to 3.0 L of 0.20 M NH3(aq) at 25ºC? (Kb of ammonia = 1.8 × 10‒5 ; assuming the volume of solution does not change after adding NH4Cl)
(A) 0.36
(B) 0.72
(C) 1.08
(D) 3.6
(E) None of the above.
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統計: A(22), B(5), C(55), D(2), E(9) #2016172
統計: A(22), B(5), C(55), D(2), E(9) #2016172
詳解 (共 2 筆)
#6033243
70. To form a buffer solution with pH = 9.0, how many moles of NH4Cl should be added to 3.0 L of 0.20 M NH3(aq) at 25ºC? (Kb of ammonia = 1.8 × 10‒5 ; assuming the volume of solution does not change after adding NH4Cl)
(A) 0.36
(B) 0.72
(C) 1.08
(D) 3.6
(E) None of the above.
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使用Henderson-Hasselbalch equation
[OH-]=Kb*[HB]/[B+]
pOH=pKb+log[B+]/[HB]
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pH=9.0 -> (25度水,pKw =14.0 ) -> pOH=5.0
Kb=1.8 × 10‒5, pKb= -[log(1.8)+log(10-5)] = 5-0.25 = 4.75
[HB]=0.2 ,log[HB]=(log2)-(log10) = 0.301-1 = -0.7
[B+]= x mole/3L NH4Cl
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代入下式:
pOH=pKb+log[B+]/[HB]
5.0 = 4.75 + log[B+]-(-0.7)
-0.45= log[B+],為了去Log,兩邊以10為底
10-0.45=[B+]
10(0.55-1)=[B+]
0.1*3.6=[B+],得[B+]為0.36 (M)
題目問mole數,0.36(M)* 3(L)= 1.08
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