試卷名稱:112年 - 112 學士後醫學系招生考試:物理及化學#114227
年份:112年
科目:學士後西醫物理及化學
82. Using the data shown as follows to calculate ΔG° for the reaction (1 F = 96,485 coulombs): Fe(s) + Cu2+(aq) → Fe2+(aq) + Cu(s). The reduction potentials for Fe2+ and Cu2+ are as follows:
Fe2+ + 2e– → Fe ε° = –0.44 V
Cu2+ + 2e– → Cu ε° = 0.34 V
(A) –1.9 × 104 J
(B) –1.5 × 105 J
(C) 0 J
(D) 1.9 × 104 J
(E) 1.5 × 105 J