申論題

(1)

CH₃COOH = 0.01 M

CH₃COOH = CH₃COO^- + H⁺

     0.01-x            x            x

x²/ (0.01-x) = 10^-4.74

x=10^-3.37

^pH=3.37

(2)

CH₃COOH = 0.01 M*1 L / (1+0.01)L = 9.9*10^-3

CH₃COONa = 1 M * 0.01 / (1+0.01)L = 9.9*10^-3

pH=pKa+log (A^-/HA)

pH=10^-4.74+log(9.9*10^-3 / 9.9*10^-3)

pH=4.74