設A為訂到長照巴士機率;B為訂到復原巴士機率(1). P(A ∪ B) = P(A) + P(B) - P(A∩B) => 0.6 + 0.4 - 0.6x0.4 = 0.76(2). 0.6 x 0.6 = 0.36(3). P(A' ∩ B') = 1 - P(A ∪ B)' or P(A') x P(B')=> 1 - 0.76 = 0.24 or (1 - 0.6) x (1 - 0.4) = 0.24