E = K Φ n
100V => n=1000
if
Ia = 2A ,E降為99V 若要維持轉速固定,Φ需下降(因E = K Φ n ,磁通與轉速成反比 )
If = 0.4/(100/99)=0.396
Pout = 2 * 99 =198W