L,TWA (t 小時時量平均音壓級)=108=16.61×log[(D×100)/(12.5×t)]+90= 16.61×log(D×8/t)+90,.若 t=8 則上式變為 L,TWA=16.61×log(D)+90 D=100*2^[(L-90)/5].D=Dose=110%=1.1
.16.61×log(1.1)+90 ,
=16.61x0.0414+90
=90.69 db