10. CH
3COOH
(aq)+H2O(I)→H
3O
+(aq)+CH3COO
-(aq),whichdescriptionis incorrect?
(A)K
a = [H
3O+] [CH
3COO
-]/[CH
3COOH]
(B) pH = logK
a(C)H
3O
+ is the conjugate base to CH
3COOH.
(D) The K
a value of CH
3COOH is 1.7 x 10
-5, indicating it's a kind of weak acids.
(E) pKa = 4.76
詳解 (共 1 筆)
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