113年 - 113 台灣聯合大學系統_碩士班招生考試試題_化學類:無機化學#122281
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所屬科目:研究所、轉學考(插大)◆無機化學
選擇題 (40)
17. Complexes of general formula. fac-[Mo CO)3(phosphine):] have the C-O stretching frequencies as given below.
Phosphines: ( A ) PMe3: ( B ) PPh2CI; ( C ) PF3; ( D ) PCI3
One of vco (cm-1) of higher frequency: (i) 2090: (i) 2040; (iii) 1977: (iv) 1945
The correct combination of phosphine and stretching frequency is (A) ( A )-(i); ( B )-(ii): ( C )-(iii): ( D )-(iv) (B) ( A )-(iv): ( B )-(iii); ( C )-(ii): ( D )-(i) (C) ( A )-(iv): ( B )-(i): ( C )-(iii); ( D )-(ii) (D) ( A )-(iv): ( B )-(iii): ( C )-(i); ( D )-(ii) (E) ( A )-(i):( B )-(iv); ( C )-(iii): ( D )-(ii)
The correct combination of phosphine and stretching frequency is (A) ( A )-(i); ( B )-(ii): ( C )-(iii): ( D )-(iv) (B) ( A )-(iv): ( B )-(iii); ( C )-(ii): ( D )-(i) (C) ( A )-(iv): ( B )-(i): ( C )-(iii); ( D )-(ii) (D) ( A )-(iv): ( B )-(iii): ( C )-(i); ( D )-(ii) (E) ( A )-(i):( B )-(iv); ( C )-(iii): ( D )-(ii)
(A)S:2+,N:2-; (B)S:2+,0:2-;(C) Xe:2+,O:1
(D) The order in the basicities of nitrogen-based compounds is listed.
NH3<NH2Me < NH2Et < NHME2 <NHEt2 < NHBu2
(E) Both of CO and CO2 are Lewis acids.
(A) 1.(B) 2, (C)3. (D)4. or (E) 5.
(A) A : bule: B: yellow; C: purple (B) A : yellow: B: blue: C: purple (C) A: purple; B: yeillow; C: blue Ccan
(D) A: yellow; B: purple; C: blue (E) A : bule; B: purple: C: yellow
(A) 0, (B) 1, (C) 2, (D) 3, or (E) 4
(A) A is a Fischer Carbene and B is a Schrock Alkylidene.
(B) The carbene ligand in A should be described as a dianionic, 4-
electron donor, and the carbene ligand in B should be described as a
neutral, 2-electron donor.
(C) A can be prepared via a-H elimination.
(D) A tends to react with a nucleophile.
(E) B could react with BF3 to yield a carbide product.
and a large negative
.
(C) To obtain the △G for the reaction, you can measure rates of forward reaction at different temperatures to
determine rate constants, and plot In k vs. I/T.
(D) PPh3 would yield the largest value of Keq and △G for the reaction as compared to PMe3 and P(OEt)3. This
statement should be attributed to the electronic argument.
(E) The presence of higher concentration of CO should shift the equilibrium to the right.
(A) CH4 is D4h. (B) CO2 is D∞h. (C) XeF4 is C4h. (D) H2O2 is C2. (E) SO2Cl2 has the same point group to H2O.