阿摩線上測驗
23.尖頂直立圓錐錐之底面圓直徑為12m，高為8m，則其側面展開圖扇形面積為多少m2？
(A)60π
(B)75π
(C)80π
(D)125π
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統計： A(107), B(61), C(62), D(42), E(0) #401982
統計： A(107), B(61), C(62), D(42), E(0) #401982
詳解 (共 2 筆)
蔡翊桀
#1148028
側面積 = 扇形半徑×扇形半徑× π ×(扇形角÷ ３６０°)
= 10 × 10 × π × (２１６° ÷ ３６０°)
= 100 π × (6/10) = 60 π 扇形角 = (底圓圓周 ÷ 扇形圓周 )× ３６０° = (12 π ÷ 20 π )× ３６０° = ２１６°
= 10 × 10 × π × (２１６° ÷ ３６０°)
= 100 π × (6/10) = 60 π 扇形角 = (底圓圓周 ÷ 扇形圓周 )× ３６０° = (12 π ÷ 20 π )× ３６０° = ２１６°
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