阿摩線上測驗
54. The following shows a rod of length L = 10.0 cm that is forced to move at constant speed v = 5.00 m/s along horizontal rails. The rod, rails, and connecting strip at the right form a conducting loop. The rod has resistance 0.400 Ω; the rest of the loop has negligible resistance. A current i = 100 A through the long straight wire at distance a = 10.0 mm from the loop sets up a (nonuniform) magnetic field through the loop. Find the emf. (μ0 = 4π10-7 T m/A, ln 2 = 0.693, ln 10 = 2.303, ln 11 = 2.398) 
(A) 2.4✖10-4 V
(B) 5.8✖10-3 V
(C) 4.8✖10-5 V
(D) 3.9✖10-4 V
(E) 8.8✖10-4 V
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統計： A(26), B(0), C(3), D(0), E(0) #2020498
統計： A(26), B(0), C(3), D(0), E(0) #2020498
詳解 (共 1 筆)
面試倒楣鬼-22幸運上後西
#4797135
B = μ0*100 / 2πR , emf= v*BdL (此處B不平均) -> 5*μ0*100(ln11)/ 2π ~= 2.4*10-4 (A)
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