12．Let 'v' and 's' both be binary electron degrees of freedom, with v = K or K', and s = U or D. Below, we will use the following convention: a) A notation such as |K, U) represents an one-electronstate with v = K, and s = U; b) Aproduct such as |K, U)|K', D) denotes a two-electron state with the 1st electron in the state K, U) and the 2nd in |K', D). Which of the following states are consistentwith the Pauli exclusion principle?(A)|K,U＞|K',D＞ - |K',U＞|K,D＞ (B)|K,U＞|K',U＞ - |K',U＞|K,U＞ (C)|K,U＞|K',U＞ - |K',D＞|K,D＞ (D)|K,U＞|K',D＞ - |K',D＞|K,U＞ (E)None of the above

1. For a particle with an energy of E tunneling through a finite barrier height of U and width of & solve the Schrodinger wave equation to calculate the tunneling probability and select the correct answer corresponding to various E, U, and 8 for different particles. (A) For a neutron with E = 50 meV incident on a barrier of U = 250 meV and 8 = 0.16 nm, the tunneling probability is 4.45×10-11 = 0.0445 ppb (B) For a neutron with E = 50 meV incident on a barrier of U = 250 meV and 8 = 0.1 nm, the tunneling probability is 5.86×10-10 = 0.586 ppb (C) For an electron with E = 1.0 eV incident on a barrier with U = 5.0 eV and 8 = 0.5 nm, the tunneling probability is 7.1×10-7 = 0.71 ppm (D) For an electron with E = 1.0 eV incident on a barrier with U = 5.0 eV and 8 = 1.0 nm, the tunneling probability is 2.52×10-9 =2.52 ppb (E) For an electron with E = 1.0 eV incident on a barrier with U = 5.0 eV and & = 1.25 nm, the tunneling probability is 1.5×10-10 = 0.15 ppb

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