12. A possible mechanism for the overall reaction: Br2(g) + 2NO(g)→ 2NOBr(g) : NO(g) + Br2(g) ←→ NOBr2(g) (fast; rate constant for forward reaction is k1 and k-1 for reverse reaction) NOBr2(g) + NO(g)→ 2NOBr2(g) (slow; rate constant is k2) The rate law for formation of NOBr based on this mechanism is rate = ________.
(A)k1[NO]½
(B)k1[Br
(C) (k2k1/k-1)[NO]²[Br₂]
(D)(k1/k-1)2[NO]²
(E)k2[NOBr2][NO]

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統計: A(0), B(0), C(10), D(0), E(4) #2343733