試題詳解

12. A possible mechanism for the overall reaction: Br_2(g) + 2NO_(g)→ 2NOBr_(g) : NO_(g) + Br_2(g) ←→ NOBr_2(g) (fast; rate constant for forward reaction is k₁ and k_-1 for reverse reaction) NOBr_2(g) + NO_(g)→ 2NOBr_2(g) (slow; rate constant is k₂) The rate law for formation of NOBr based on this mechanism is rate = ________.
(A)k₁[NO]½
(B)k₁[Br_₂]½
(C) (k₂k₁/k_-1)[NO]²[Br₂]
(D)(k₁/k_-1)2[NO]²
(E)k₂[NOBr₂][NO]