13.Why do acetal-forming reactions that use ethylene glycol (HOCH2CH2OH) have more favorable equilibrium constants than those using methanol? (A) Ethylene glycol reacts more rapidly. (B) They are more favorable on entropy grounds. (C) They are more favorable on enthalpy grounds. (D) Ethylene glycol is acidic and catalyzes the reaction. (E) The ethylene acetal can serve as a protecting group.