38. Phenylketonuria (PKU) is due to a recessive allele. Given 1 PKU occurrence per 25 births, what is the frequency of individuals with the heterozygous phenotype if the population is in Hardy-Weinberg equilibrium?
(A) 0.2
(B) 0.32
(C) 0.64
(D) 0.8
(E) 0.96

答案:登入後查看
統計: A(2), B(77), C(1), D(1), E(1) #2052889

私人筆記 (共 2 筆)

私人筆記#5469320
未解鎖
顯性等位基因記為A而隱性等位基因記為a,...
(共 176 字,隱藏中)
前往觀看
4
1
私人筆記#7815982
未解鎖
哈溫定律(Hardy-Weinber...


(共 89 字,隱藏中)
前往觀看
2
0