五、如圖所示,為一平衡狀態之結構:
MA = WL(1/2 Sbc +Sab)+ MD - (P *Sad) = RB * SaeMA = 5*15 *( (1/2*15) +10 ) + 320 - 100 *35 = RB * 45Rb = -41.5 ↑ 故 Rb = 41.5 ↓Fy = 5*15 + 41.5 - 100 = Ra ↑Ra = 16.5