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研究所、轉學考(插大)◆特殊教育導論
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112年 - [非官方正解]112 國立臺南大學_特殊教育學系特殊教育學系輔助科技碩士班招生考試:特殊教育導論#118759
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題組內容
2.名詞釋義(每題7分,共28分)
(2)圖片兌換溝通系統 (picture exchange communication system)
其他申論題
(1)個別化轉銜計畫 (individualized transition planning)
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(3)雙重特殊需求學生 (twice exceptional)
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(4)Renzulli全校性充實模式 (Schoolwide Enrichment Model)
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(1)請舉二類須要「同步聽打」服務之特殊需求學生的例子,並說明其理由為何?
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(2)請簡要論述下列有關資賦優異教育之短文。It is commonly recognized that the development of the gifted and talented education (GATE) in Taiwan started in 1973, when the Ministry of Education launched experimental programs throughout Taiwan for academically talented elementary students. Generally speaking, the development of GATE could be divided into five stages: The dawning stage before 1973, the experimental stage (1973-1983), the promoting stage (1984-1994), the established stage (1995-2005), and the transformation stage (2006-present). Given these stages, educational practices of gifted and talented education, issues of pre- and in-service teacher education for GATE, and the current state of research in gifted education are thoroughly discussed. Finally, as a global vision of GATE in Taiwan, to develop the talent based on individual differences and enhance high-quality education, four prospects are proposed: (a) develop gifted and talented students with both smart brains and tender minds, (b) enhance quality of gifted and talented education, (c) replace the examination-oriented mind by adaptive education, and (d) take advantage of opportunities from the new system of 12-year national education. 資料來源:Wu, W.-T., & Kuo, Y.-L. (2016). Gifted and talented education in Taiwan: A 40-year journey. In D. Y. Dai & C. C. Kuo (Eds.), Gifted education in Asia: Problems and prospects (pp. 33–50). Charlotte, NC: Information Age Publishing.
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I. (50 points) Fill in the following blanks. 1. Find the tangent line to function y=3x2-5x+2 at x=2. Express your answer in the form y=mx+b with slope m and y-intercept b.___(1)__.
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2. Find the derivative of (x2 +1)(x2+3x+2),__(2)__ ; and the derivative of ,__(3)__.
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3. Let function f(x)=3x5-5x3 has domain D1=[-], then its global maximum is at __(4)__ on D1. Let function has domain D2 =[1,10], then its global minimum is at __(5)__ on D2.
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4. Suppose f(x)=x3 and x=(z-1)(z+1).Then=__(6)__. (Please express it in z.)Suppose=__ (7)__ . (Please express it in z.)
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5.Suppose=__(8)__.
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