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最新試卷
115年 - 115年證券商高級業務員、投信投顧業務員資格測驗學習指南與題庫財務分析第7章損益分析149題 1-50#138502(49題)
115年 - 115 證券商高級業務員、投信投顧業務員資格測驗學習指南與題庫證券商交易相關法規第4章證券商之管理126題 51-100#138498(50題)
115年 - 115年證券商高級業務員、投信投顧業務員資格測驗學習指南與題庫證券商交易相關法規第4章證券商之管理126題 1-50#138497(50題)
115年 - 115年證券商高級業務員、投信投顧業務員資格測驗學習指南與題庫財務分析第2章流動資產、負債與短期流動性分析84題#138491(84題)
115年 - 115 證券商高級業務員、投信投顧業務員資格測驗學習指南與題庫財務分析第3章現金流量分析及財務預測79#138488(79題)
115年 - 109 全國高級中等學校學生技藝競賽考試_工業類:室內配線#138481(25題)
115年 - 115年證券商高級業務員、投信投顧業務員資格測驗學習指南與題庫投資學第5章證券投資基本分析154題 101-154#138480(54題)
115年 - 115 證券商高級業務員、投信投顧業務員資格測驗學習指南與題庫財務分析第10章財務管理169題 51-100#138479(50題)
115年 - 115年證券商高級業務員、投信投顧業務員資格測驗學習指南與題庫投資學第2章固定收益證券分析189題 151-189#138478(39題)
115年 - 115年證券商高級業務員、投信投顧業務員資格測驗學習指南與題庫財務分析第10章財務管理169題 101-169#138477(69題)
最新試題
20. The fact that we can only calculate probabilities for values of physical quantities in quantum measurements means that (A) radiation and matter are not described by mathematical relations between measurements. (B) the probabilities cannot be calculated from mathematical relationships. (C) the results of physical measurements bear no relationship to theory. (D) the average values of a large number of measurements correspond to the calculated probabilities. (E) the average of the values calculated in a large number of different theories corresponds to the results of a measurement.
19. Suppose Bohr had chosen the potential energy of the electron in the hydrogen atom to be V = 0 when the electron is in the orbit with n = 1. He could do this by (A) choosing n = 1 for the orbit where the kinetic energy of the electron is zero. (B) adding a constant 13.6 eV to the potential energy for all values of n. (C) adding a constant 27.2 eV to the potential energy for all values of n. (D) subtracting a constant 13.6 eV from the potential energy for all values of n. (E) subtracting a constant 27.2 eV from the potential energy for all values of n.
18. The number of photons per second passing a plane perpendicular to a collimated monochromatic (one frequency) beam of light transporting power P is directly proportional to (A) the wavelength of the light. (B) the frequency of the light. (C) the power of the beam. (D) all of the above. (E) only ( A ) and ( C ) above.
最新申論題
8. A hoop, a solid cylinder, and a solid sphere all have the same mass m and the same radius R. Each is mounted to oscillate about an axis a distance 0.5R from the center. The axis is perpendicular to the circular plane of the hoop and the cylinder and to an equatorial plane of the sphere as shown below. Which is the correct ranking in order of increasing angular frequency ω (from highest to lowest)?
7. A segment of wire carries a current of 25 A along the x axis from x = −2.0 m to x = 0, and then along the z axis from z = 0 to z = 3.0 m. In this region of space, the magnetic field is equal to 40 mT in the positive z direction. What is the magnitude of the force on this segment of wire?
6. How much energy is dissipated as heat during a two-minute time interval by a 1.5-kΩ resistor which has a constant 20-V potential difference across its leads?
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22. 的最佳合成方法是 (A) (1) Mg, Et2O (2) D2O (B) (1) LiAlD4, Et2O (2) D2O (C) (1) HOCH2CH2OH, H+ (2) Mg, Et2O (3) D2O (4) H2O, H+ (D) (1) HOCH2CH2OH, H+ (2) DCl (3) H2O, H+
61.下列有關隱球菌病(cryptococcosis)之敘述,何者錯誤? (A)Cryptococcus magnus會引起貓的外耳炎 (B)Cryptococcus neoformans會引起貓的胃腸炎 (C)隱球菌在鴿舍的鳥糞中可存活2年以上 (D)犬比貓更容易造成嚴重散發性感染
複選題30.有關《社會秩序維護法》之處罰,下列敘述何者正確?(A)警察機關對於情節輕微而事實明確之違反本法案件,得不經通知、訊問逕行處分(B)單獨宣告沒入案件,警察機關於訊問後,應即移送地方法院簡易庭裁定(C)警察機關移請裁定之案件,簡易庭認為不應處罰者,得逕為不罰之裁定(D)違序行為之情節可憫恕者,處申誡或免除其處罰(E)裁處後3個月內,再有違序行為者,得加重處罰
23.下列何者具有組成腎臟過濾膜(filtration membrane)的構造? (A)鮑氏囊臟層(visceral layer of Bowman's capsule) (B)近曲小管(proximal convoluted tubule) (C)集尿管(collecting duct) (D)亨利氏環(loop of Henle)
複選題38.下列何者為相牽連案件?(A)甲犯下重傷罪,羈押期間,乙為使其逃跑而觸犯便利脫逃罪(B)丙在台北車站觸犯放火罪,隔天在某銀樓觸犯強盜罪(C)丁、戊共犯加重詐欺罪(D)己、庚同時在同一大賣場各自犯竊盜罪(E)壬觸犯殺人罪,癸為掩飾其犯行而觸犯湮滅證據罪
4.有一多醣是由n個葡萄糖(C6H12O6)單體經脫去(n-1)個水分子聚合而成,其反應為nC6H12O6 → C6nH10n+2O5n+1+(n-1)H2O 將10.0 g的此一多醣配成1.0 L的溶液,在27℃時測得其滲透壓為88.0 mmHg,則此多醣是由_______個葡萄糖單體聚合而成。