4. 某船於DRλ49°W,CE19分27秒(Fast),當時天文鐘(CT)讀數為05-22-00,此時鐘時 (WT)為02-01-53求錶差(WE)?
(A)40秒(Slow)
(B)40秒(Fast)
(C)1分10秒(Slow)
(D)1分10秒(Fast)

答案:登入後查看
統計: A(29), B(17), C(9), D(3), E(0) #3459858

詳解 (共 1 筆)

#6524149
GMT=CT-CE
05:22:00 - 00:19:27 = 05:02:33
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LMT=49W/15=-3H16M
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LMT=GMT-時差
05:02:33 - 03:16:00 = 01:46:33
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WT - LMT = 鐘差
02:01:53 - 01:46:33 = 00:15:20
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