4 試求反拉氏轉換(Inverse Laplace Transform) L−1 {(3s − 2)/[s 2 + 6s + 25]}:
(A)3cos 2t − 2sin 2t
(B) 3 e− 3t cos2t −2e−3 t sin 2t
(C) 3e −3t cos4t −2.75e−3t sin4t
(D)e−3t cos2t −e−3t sin 2t
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統計: A(2), B(0), C(2), D(0), E(0) #1050223
統計: A(2), B(0), C(2), D(0), E(0) #1050223